In Chelyabinsk lives a much respected businessman Nikita with a strange nickname "Boss". Once Nikita decided to go with his friend Alex to the Summer Biathlon World Cup. Nikita, as a very important person, received a token which allows to place bets on each section no more than on one competitor.To begin with friends learned the rules: in the race there are n sections of equal length and m participants. The participants numbered from 1 to m. About each participant the following is known: li — the number of the starting section,  ri — the number of the finishing section (li ≤ ri), ti — the time a biathlete needs to complete an section of the path, ci — the profit in roubles. If the i-th sportsman wins on one of the sections, the profit will be given to the man who had placed a bet on that sportsman. The i-th biathlete passes the sections from li to ri inclusive. The competitor runs the whole way in (ri - li + 1)·ti time units. It takes him exactly ti time units to pass each section. In case of the athlete's victory on k sections the man who has betted on him receives k·ci roubles.In each section the winner is determined independently as follows: if there is at least one biathlete running this in this section, then among all of them the winner is the one who has ran this section in minimum time (spent minimum time passing this section). In case of equality of times the athlete with the smaller index number wins. If there are no participants in this section, then the winner in this section in not determined. We have to say that in the summer biathlon all the participants are moving at a constant speed.We should also add that Nikita can bet on each section and on any contestant running in this section.Help the friends find the maximum possible profit.

The first line contains two integers n and m (1 ≤ n, m ≤ 100). Then follow m lines, each containing 4 integers li, ri, ti, ci (1 ≤ li ≤ ri ≤ n, 1 ≤ ti, ci ≤ 1000).

Print a single integer, the maximal profit in roubles that the friends can get. In each of n sections it is not allowed to place bets on more than one sportsman.

NoteIn the first test the optimal bet is: in the 1-2 sections on biathlete 1, in section 3 on biathlete 3, in section 4 on biathlete 4. Total: profit of 5 rubles for 1 section, the profit of 5 rubles for 2 section, profit of 30 rubles for a 3 section, profit of 20 rubles for 4 section. Total profit 60 rubles.In the second test the optimal bet is: on 1 and 5 sections on biathlete 1, in the 2-4 sections on biathlete 2, in the 6-7 sections on athlete 4. There is no winner in the 8 section. Total: profit of 10 rubles for 1 section, the profit of 15 rubles for 2,3,4 section, profit of 10 rubles for a 5 section, profit of 20 rubles for 6, 7 section. Total profit 105 rubles.


A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.

The first line contains a positive integer n (1 ≤ n ≤ 100), then follow n lines containing three integers each: the xi coordinate, the yi coordinate and the zi coordinate of the force vector, applied to the body ( - 100 ≤ xi, yi, zi ≤ 100).

Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.


In one school with Vasya there is a student Kostya. Kostya does not like physics, he likes different online games. Every day, having come home, Kostya throws his bag in the farthest corner and sits down at his beloved computer. Kostya even eats glued to the game. A few days ago Kostya bought a new RPG game "HaresButtle", which differs from all other games in this genre. It has a huge number of artifacts. As we know, artifacts are divided into basic and composite ones. Only the basic artifacts are available on sale. More powerful composite artifacts are collected from some number of basic artifacts.After the composing composite artifact, all the components disappear.Kostya is the head of the alliance, so he has to remember, what artifacts has not only himself, but also his allies. You must identify by sequence of artifacts purchased by Kostya and his allies, how many and which artifacts has been collected by each of them. It is believed that initially no one has any artifacts.

The first line has 4 natural numbers: k (1 ≤ k ≤ 100) — the number of Kostya's allies, n (1 ≤ n ≤ 50) — the number of basic artifacts, m (0 ≤ m ≤ 50) — the number of composite artifacts, q (1 ≤ q ≤ 500) — the number of his friends' purchases. The following n lines contain the names of basic artifacts. After them m lines contain the descriptions of composite artifacts in the following format: <Art. Name>: <Art. №1> <Art. №1 Number>, <Art. №2> <Art. №2 Number>, ... <Art. №X> <Art. №Х Number> All the numbers are natural numbers not exceeding 100 (1 ≤ X ≤ n). The names of all artifacts are different, they are composed of lowercase Latin letters, and the length of each name is from 1 to 100 characters inclusive. All the words in the format of the description of a composite artifact are separated by exactly one space. It is guaranteed that all components of the new artifact are different and have already been met in the input data as the names of basic artifacts.  Next, each of the following q lines is characterized by the number ai, the number of a friend who has bought the artifact (1 ≤ ai ≤ k), and the name of the purchased basic artifact. Let's assume that the backpacks of the heroes are infinitely large and any artifact bought later can fit in there. It is guaranteed that after the i-th purchase no more than one opportunity to collect the composite artifact appears. If such an opportunity arose, the hero must take advantage of it.

The output file should consist of k blocks. The first line should contain number bi — the number of different artifacts the i-th ally has. Then the block should contain bi lines with the names of these artifacts and the number of these artifacts. At that the lines should be printed in accordance with the lexicographical order of the names of the artifacts. In each block all the artifacts must be different, and all the numbers except the bi should be positive.

2 3 2 5
desolator
refresher
perseverance
vanguard: desolator 1, refresher 1
maelstorm: perseverance 2
1 desolator
2 perseverance
1 refresher
2 desolator
2 perseverance


Anton and Dasha like to play different games during breaks on checkered paper. By the 11th grade they managed to play all the games of this type and asked Vova the programmer to come up with a new game. Vova suggested to them to play a game under the code name "dot" with the following rules:  On the checkered paper a coordinate system is drawn. A dot is initially put in the position (x, y).  A move is shifting a dot to one of the pre-selected vectors. Also each player can once per game symmetrically reflect a dot relatively to the line y = x.  Anton and Dasha take turns. Anton goes first.  The player after whose move the distance from the dot to the coordinates' origin exceeds d, loses. Help them to determine the winner.

The first line of the input file contains 4 integers x, y, n, d ( - 200 ≤ x, y ≤ 200, 1 ≤ d ≤ 200, 1 ≤ n ≤ 20) — the initial coordinates of the dot, the distance d and the number of vectors. It is guaranteed that the initial dot is at the distance less than d from the origin of the coordinates. The following n lines each contain two non-negative numbers xi and yi (0 ≤ xi, yi ≤ 200) — the coordinates of the i-th vector. It is guaranteed that all the vectors are nonzero and different.

You should print "Anton", if the winner is Anton in case of both players play the game optimally, and "Dasha" otherwise.

NoteIn the first test, Anton goes to the vector (1;2), and Dasha loses. In the second test Dasha with her first move shifts the dot so that its coordinates are (2;3), and Anton loses, as he has the only possible move — to reflect relatively to the line y = x. Dasha will respond to it with the same move and return the dot in position (2;3).


Programmer Sasha has recently begun to study data structures. His coach Stas told him to solve the problem of finding a minimum on the segment of the array in , which Sasha coped with. For Sasha not to think that he had learned all, Stas gave him a new task. For each segment of the fixed length Sasha must find the maximum element of those that occur on the given segment exactly once. Help Sasha solve this problem.

The first line contains two positive integers n and k (1 ≤ n ≤ 105, 1 ≤ k ≤ n) — the number of array elements and the length of the segment.  Then follow n lines: the i-th one contains a single number ai ( - 109 ≤ ai ≤ 109).

Print n–k + 1 numbers, one per line: on the i-th line print of the maximum number of those numbers from the subarray ai ai + 1 … ai + k - 1 that occur in this subarray exactly 1 time. If there are no such numbers in this subarray, print "Nothing".


Fangy the little walrus, as all the modern walruses, loves to communicate via text messaging. One day he faced the following problem: When he sends large texts, they are split into parts each containing n characters (which is the size of one text message). Thus, whole sentences and words get split!Fangy did not like it, so he faced the task of breaking the text into minimal messages on his own so that no sentence were broken into pieces when it is sent and the number of text messages to be sent would be minimal. If two consecutive sentences are in different messages, the space between them can be ignored (Fangy does not write this space).The little walrus's text looks in the following manner: TEXT ::= SENTENCE | SENTENCE SPACE TEXTSENTENCE ::= WORD SPACE SENTENCE | WORD ENDEND ::= {'.', '?', '!'}WORD ::= LETTER | LETTER WORDLETTER ::= {'a'..'z', 'A'..'Z'}SPACE ::= ' 'SPACE stands for the symbol of a space.So, how many messages did Fangy send?

The first line contains an integer n, which is the size of one message (2 ≤ n ≤ 255). The second line contains the text. The length of the text does not exceed 104 characters. It is guaranteed that the text satisfies the above described format. Specifically, this implies that the text is not empty.

On the first and only line print the number of text messages Fangy will need. If it is impossible to split the text, print "Impossible" without the quotes.

NoteLet's take a look at the third sample. The text will be split into three messages: "Hello!", "Do you like fish?" and "Why?".


Once a walrus professor Plato asked his programming students to perform the following practical task. The students had to implement such a data structure that would support a convex hull on some set of points S. The input to the program had q queries of two types: 1. Add a point with coordinates (x, y) into the set S. Note that in this case the convex hull of S could have changed, and could have remained the same. 2. Say whether a point with coordinates (x, y) belongs to an area limited by the convex hull, including the border. All the students coped with the task. What about you?

The first line contains an integer q (4 ≤ q ≤ 105).  Then follow q lines in the following way: "t x y", where t is the query type (1 or 2), and (x, y) are the coordinates of the point ( - 106 ≤ x, y ≤ 106, x and y are integers).  There is at least one query of type 2. It is guaranteed that the three queries of the first type follow first and the points given in the queries form a non-degenerative triangle. Also all the points added in S are distinct.

For each query of the second type print one string containing "YES", if the point lies inside the convex hull or on its border. Otherwise, print "NO".


In Walrusland public transport tickets are characterized by two integers: by the number of the series and by the number of the ticket in the series. Let the series number be represented by a and the ticket number — by b, then a ticket is described by the ordered pair of numbers (a, b). The walruses believe that a ticket is lucky if a * b = rev(a) * rev(b). The function rev(x) reverses a number written in the decimal system, at that the leading zeroes disappear. For example, rev(12343) = 34321, rev(1200) = 21.The Public Transport Management Committee wants to release x series, each containing y tickets, so that at least w lucky tickets were released and the total number of released tickets (x * y) were minimum. The series are numbered from 1 to x inclusive. The tickets in each series are numbered from 1 to y inclusive. The Transport Committee cannot release more than maxx series and more than maxy tickets in one series.

The first line contains three integers maxx, maxy, w (1 ≤ maxx, maxy ≤ 105, 1 ≤ w ≤ 107).

Print on a single line two space-separated numbers, the x and the y. If there are several possible variants, print any of them. If such x and y do not exist, print a single number  - 1.


Thought it is already the XXI century, the Mass Media isn't very popular in Walrusland. The cities get news from messengers who can only travel along roads. The network of roads in Walrusland is built so that it is possible to get to any city from any other one in exactly one way, and the roads' lengths are equal.The North Pole governor decided to carry out an information reform. Several cities were decided to be chosen and made regional centers. Maintaining a region center takes k fishlars (which is a local currency) per year. It is assumed that a regional center always has information on the latest news.For every city which is not a regional center, it was decided to appoint a regional center which will be responsible for keeping this city informed. In that case the maintenance costs will be equal to dlen fishlars per year, where len is the distance from a city to the corresponding regional center, measured in the number of roads along which one needs to go.Your task is to minimize the costs to carry out the reform.

The first line contains two given numbers n and k (1 ≤ n ≤ 180, 1 ≤ k ≤ 105). The second line contains n - 1 integers di, numbered starting with 1 (di ≤ di + 1, 0 ≤ di ≤ 105). Next n - 1 lines contain the pairs of cities connected by a road.

On the first line print the minimum number of fishlars needed for a year's maintenance. On the second line print n numbers, where the i-th number will represent the number of the regional center, appointed to the i-th city. If the i-th city is a regional center itself, then you should print number i. If there are several solutions to that problem, print any of them.


Fangy collects cookies. Once he decided to take a box and put cookies into it in some way. If we take a square k × k in size, divided into blocks 1 × 1 in size and paint there the main diagonal together with cells, which lie above it, then the painted area will be equal to the area occupied by one cookie k in size. Fangy also has a box with a square base 2n × 2n, divided into blocks 1 × 1 in size. In a box the cookies should not overlap, and they should not be turned over or rotated. See cookies of sizes 2 and 4 respectively on the figure:    To stack the cookies the little walrus uses the following algorithm. He takes out of the repository the largest cookie which can fit in some place in the box and puts it there. Everything could be perfect but alas, in the repository the little walrus has infinitely many cookies of size 2 and larger, and there are no cookies of size 1, therefore, empty cells will remain in the box. Fangy wants to know how many empty cells will be left in the end.

The first line contains a single integer n (0 ≤ n ≤ 1000).

Print the single number, equal to the number of empty cells in the box. The answer should be printed modulo 106 + 3.

NoteIf the box possesses the base of 23 × 23 (as in the example), then the cookies will be put there in the following manner:


Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.Thus, "localization" will be spelt as "l10n", and "internationalization» will be spelt as "i18n".You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes.

The first line contains an integer n (1 ≤ n ≤ 100). Each of the following n lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters.

Print n lines. The i-th line should contain the result of replacing of the i-th word from the input data.

4
word
localization
internationalization
pneumonoultramicroscopicsilicovolcanoconiosis


A progress bar is an element of graphical interface that displays the progress of a process for this very moment before it is completed. Let's take a look at the following form of such a bar.A bar is represented as n squares, located in line. To add clarity, let's number them with positive integers from 1 to n from the left to the right. Each square has saturation (ai for the i-th square), which is measured by an integer from 0 to k. When the bar for some i (1 ≤ i ≤ n) is displayed, squares 1, 2, ... , i - 1 has the saturation k, squares i + 1, i + 2, ... , n has the saturation 0, and the saturation of the square i can have any value from 0 to k.So some first squares of the progress bar always have the saturation k. Some last squares always have the saturation 0. And there is no more than one square that has the saturation different from 0 and k.The degree of the process's completion is measured in percents. Let the process be t% completed. Then the following inequation is fulfilled: An example of such a bar can be seen on the picture.  For the given n, k, t determine the measures of saturation for all the squares ai of the progress bar.

We are given 3 space-separated integers n, k, t (1 ≤ n, k ≤ 100, 0 ≤ t ≤ 100).

Print n numbers. The i-th of them should be equal to ai.


Vasya has a pack of 54 cards (52 standard cards and 2 distinct jokers). That is all he has at the moment. Not to die from boredom, Vasya plays Solitaire with them.Vasya lays out nm cards as a rectangle n × m. If there are jokers among them, then Vasya should change them with some of the rest of 54 - nm cards (which are not layed out) so that there were no jokers left. Vasya can pick the cards to replace the jokers arbitrarily. Remember, that each card presents in pack exactly once (i. e. in a single copy). Vasya tries to perform the replacements so that the solitaire was solved.Vasya thinks that the solitaire is solved if after the jokers are replaced, there exist two non-overlapping squares 3 × 3, inside each of which all the cards either have the same suit, or pairwise different ranks.Determine by the initial position whether the solitaire can be solved or not. If it can be solved, show the way in which it is possible.

The first line contains integers n and m (3 ≤ n, m ≤ 17, n × m ≤ 52). Next n lines contain m words each. Each word consists of two letters. The jokers are defined as "J1" and "J2" correspondingly. For the rest of the cards, the first letter stands for the rank and the second one — for the suit. The possible ranks are: "2", "3", "4", "5", "6", "7", "8", "9", "T", "J", "Q", "K" and "A". The possible suits are: "C", "D", "H" and "S". All the cards are different.

If the Solitaire can be solved, print on the first line "Solution exists." without the quotes. On the second line print in what way the jokers can be replaced. Three variants are possible:   "There are no jokers.", if there are no jokers in the input data. "Replace Jx with y.", if there is one joker. x is its number, and y is the card it should be replaced with. "Replace J1 with x and J2 with y.", if both jokers are present in the input data. x and y here represent distinct cards with which one should replace the first and the second jokers correspondingly. On the third line print the coordinates of the upper left corner of the first square 3 × 3 in the format "Put the first square to (r, c).", where r and c are the row and the column correspondingly. In the same manner print on the fourth line the coordinates of the second square 3 × 3 in the format "Put the second square to (r, c).". If there are several solutions to that problem, print any of them. If there are no solutions, print of the single line "No solution." without the quotes. See the samples to understand the output format better.

NoteThe pretests cover all the possible output formats.

4 6
2S 3S 4S 7S 8S AS
5H 6H 7H 5S TC AC
8H 9H TH 7C 8C 9C
2D 2C 3C 4C 5C 6C

4 6
2S 3S 4S 7S 8S AS
5H 6H 7H J1 TC AC
8H 9H TH 7C 8C 9C
2D 2C 3C 4C 5C 6C

4 6
2S 3S 4S 7S 8S AS
5H 6H 7H QC TC AC
8H 9H TH 7C 8C 9C
2D 2C 3C 4C 5C 6C

Solution exists.
Replace J1 with 2H.
Put the first square to (1, 1).
Put the second square to (2, 4).

Solution exists.
There are no jokers.
Put the first square to (1, 1).
Put the second square to (2, 4).


There is the following puzzle popular among nuclear physicists.A reactor contains a set of n atoms of some chemical elements. We shall understand the phrase "atomic number" as the number of this atom's element in the periodic table of the chemical elements.You are allowed to take any two different atoms and fuse a new one from them. That results in a new atom, whose number is equal to the sum of the numbers of original atoms. The fusion operation can be performed several times.The aim is getting a new pregiven set of k atoms.The puzzle's difficulty is that it is only allowed to fuse two atoms into one, it is not allowed to split an atom into several atoms. You are suggested to try to solve the puzzle.

The first line contains two integers n and k (1 ≤ k ≤ n ≤ 17). The second line contains space-separated symbols of elements of n atoms, which are available from the start. The third line contains space-separated symbols of elements of k atoms which need to be the result of the fusion. The symbols of the elements coincide with the symbols from the periodic table of the chemical elements. The atomic numbers do not exceed 100 (elements possessing larger numbers are highly unstable). Some atoms can have identical numbers (that is, there can be several atoms of the same element). The sum of numbers of initial atoms is equal to the sum of numbers of the atoms that need to be synthesized.

If it is impossible to synthesize the required atoms, print "NO" without the quotes. Otherwise, print on the first line «YES», and on the next k lines print the way of synthesizing each of k atoms as equations. Each equation has the following form: "x1+x2+...+xt->yi", where xj is the symbol of the element of some atom from the original set, and yi is the symbol of the element of some atom from the resulting set. Each atom from the input data should occur in the output data exactly one time. The order of summands in the equations, as well as the output order does not matter. If there are several solutions, print any of them. For a better understanding of the output format, see the samples.

NoteThe reactions from the first example possess the following form (the atomic number is written below and to the left of the element):To find a periodic table of the chemical elements, you may use your favorite search engine.The pretest set contains each of the first 100 elements of the periodic table at least once. You can use that information to check for misprints.

YES
Mn+C+K->Sn
Co+Zn+Sc->Pt
Li+Mg+P+F->Y


There are n knights sitting at the Round Table at an equal distance from each other. Each of them is either in a good or in a bad mood.Merlin, the wizard predicted to King Arthur that the next month will turn out to be particularly fortunate if the regular polygon can be found. On all vertices of the polygon knights in a good mood should be located. Otherwise, the next month will bring misfortunes.A convex polygon is regular if all its sides have same length and all his angles are equal. In this problem we consider only regular polygons with at least 3 vertices, i. e. only nondegenerated.On a picture below some examples of such polygons are present. Green points mean knights in a good mood. Red points mean ones in a bad mood.  King Arthur knows the knights' moods. Help him find out if the next month will be fortunate or not.

The first line contains number n, which is the number of knights at the round table (3 ≤ n ≤ 105). The second line contains space-separated moods of all the n knights in the order of passing them around the table. "1" means that the knight is in a good mood an "0" means that he is in a bad mood.

Print "YES" without the quotes if the following month will turn out to be lucky. Otherwise, print "NO".


Vasya plays The Elder Trolls IV: Oblivon. Oh, those creators of computer games! What they do not come up with! Absolutely unique monsters have been added to the The Elder Trolls IV: Oblivon. One of these monsters is Unkillable Slug. Why it is "Unkillable"? Firstly, because it can be killed with cutting weapon only, so lovers of two-handed amber hammers should find suitable knife themselves. Secondly, it is necessary to make so many cutting strokes to Unkillable Slug. Extremely many. Too many! Vasya has already promoted his character to 80-th level and in order to gain level 81 he was asked to kill Unkillable Slug. The monster has a very interesting shape. It looks like a rectangular parallelepiped with size x × y × z, consisting of undestructable cells 1 × 1 × 1. At one stroke Vasya can cut the Slug along an imaginary grid, i.e. cut with a plane parallel to one of the parallelepiped side. Monster dies when amount of parts it is divided reaches some critical value.All parts of monster do not fall after each cut, they remains exactly on its places. I. e. Vasya can cut several parts with one cut.Vasya wants to know what the maximum number of pieces he can cut the Unkillable Slug into striking him at most k times.Vasya's character uses absolutely thin sword with infinite length.

The first line of input contains four integer numbers x, y, z, k (1 ≤ x, y, z ≤ 106, 0 ≤ k ≤ 109).

Output the only number — the answer for the problem. Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).

NoteIn the first sample Vasya make 3 pairwise perpendicular cuts. He cuts monster on two parts with the first cut, then he divides each part on two with the second cut, and finally he divides each of the 4 parts on two.


Vasya plays FreeDiv. In this game he manages a huge state, which has n cities and m two-way roads between them. Unfortunately, not from every city you can reach any other one moving along these roads. Therefore Vasya decided to divide the state into provinces so that in every province, one could reach from every city all the cities of the province, but there are no roads between provinces. Unlike other turn-based strategies, in FreeDiv a player has the opportunity to build tunnels between cities. The tunnels are two-way roads along which one can move armies undetected by the enemy. However, no more than one tunnel can be connected to each city. As for Vasya, he wants to build a network of tunnels so that any pair of cities in his state were reachable by some path consisting of roads and a tunnels. But at that no more than k tunnels are connected to each province (otherwise, the province will be difficult to keep in case other provinces are captured by enemy armies).Vasya discovered that maybe he will not be able to build such a network for the current condition of the state. Maybe he'll have first to build several roads between cities in different provinces to merge the provinces. Your task is to determine the minimum number of roads Vasya needs to build so that it was possible to build the required network of tunnels in the resulting state.

The first line contains three integers n, m and k (1 ≤ n, k ≤ 106, 0 ≤ m ≤ 106). Each of the next m lines contains two integers. They are the numbers of cities connected by a corresponding road. No road connects city to itself and there is at most one road between each pair of cities.

Print a single number, the minimum number of additional roads.

NoteIn the first example only one province exists, so it is not necessary to build any tunnels or roads.In the second example two provinces exist. It is possible to merge the provinces by building a tunnel between cities 1 and 3.In the third example at least one additional road is necessary. For example it is possible to build additional road between cities 1 and 2 and build two tunnels between cities 1 and 3, 2 and 4 after that.


Vasya plays the LionAge II. He was bored of playing with a stupid computer, so he installed this popular MMORPG, to fight with his friends. Vasya came up with the name of his character — non-empty string s, consisting of a lowercase Latin letters. However, in order not to put up a front of friends, Vasya has decided to change no more than k letters of the character name so that the new name sounded as good as possible. Euphony of the line is defined as follows: for each pair of adjacent letters x and y (x immediately precedes y) the bonus c(x, y) is added to the result. Your task is to determine what the greatest Euphony can be obtained by changing at most k letters in the name of the Vasya's character.

The first line contains character's name s and an integer number k (0 ≤ k ≤ 100). The length of the nonempty string s does not exceed 100. The second line contains an integer number n (0 ≤ n ≤ 676) — amount of pairs of letters, giving bonus to the euphony. The next n lines contain description of these pairs «x y c», which means that sequence xy gives bonus c (x, y — lowercase Latin letters,  - 1000 ≤ c ≤ 1000). It is guaranteed that no pair x y mentioned twice in the input data.

Output the only number — maximum possible euphony оf the new character's name.

NoteIn the first example the most euphony name will be looser. It is easy to calculate that its euphony is 36.

abcdef 1
5
a b -10
b c 5
c d 5
d e 5
e f 5


Vasya plays The Elder Trolls III: Morrowindows. He has a huge list of items in the inventory, however, there is no limits on the size of things. Vasya does not know the total amount of items but he is sure that are not more than x and not less than 2 items in his inventory. A new patch for the game appeared to view inventory in n different modes. Displaying in mode i is a partition of all inventory items on pages, each of which (except for maybe the last one) shows exactly ai items. In addition, each mode shows how many pages bi is in a complete list. Great! Perhaps this information will be enough for Vasya to find the required number. Moreover, it is very interesting, what is the fewest number of modes in which Vasya can see inventory to determine the number of items in it?Vasya cannot use the information that was received while looking on inventory in some mode for selection of next actions. I. e. Vasya chooses some set of modes first, and then sees all the results and determines the size.Knowing the number of ai, x and assuming that Vasya is very smart, check whether he can uniquely determine the number of items in his inventory, and how many modes he will need to do that if he knows numbers ai, x and he is able to know number bi after viewing items in mode i.

The first line contains two integers n and x (0 ≤ n ≤ 105, 2 ≤ x ≤ 109). The second line contains integers ai (1 ≤ ai ≤ 109). Some numbers among all ai may be equal.

Output the fewest amount of modes required to uniquely determine amount of items in the inventory. If there is no solution output  - 1.

NoteIn the second example Vasya is not able to determine items count uniquely because 3 items, as well as 4 items, can be displayed on two pages.


Vasya plays the Plane of Tanks. The tanks in this game keep trying to finish each other off. But your "Pedalny" is not like that... He just needs to drive in a straight line from point A to point B on the plane. Unfortunately, on the same plane are n enemy tanks. We shall regard all the tanks as points. At the initial moment of time Pedalny is at the point A. Enemy tanks would be happy to destroy it immediately, but initially their turrets are tuned in other directions. Specifically, for each tank we know the initial rotation of the turret ai (the angle in radians relative to the OX axis in the counterclockwise direction) and the maximum speed of rotation of the turret wi (radians per second). If at any point of time a tank turret will be aimed precisely at the tank Pedalny, then the enemy fires and it never misses. Pedalny can endure no more than k shots. Gun reloading takes very much time, so we can assume that every enemy will produce no more than one shot. Your task is to determine what minimum speed of v Pedalny must have to get to the point B. It is believed that Pedalny is able to instantly develop the speed of v, and the first k shots at him do not reduce the speed and do not change the coordinates of the tank.

The first line contains 4 numbers – the coordinates of points A and B (in meters), the points do not coincide. On the second line number n is given (1 ≤ n ≤ 104). It is the number of enemy tanks. Each of the following n lines contain the coordinates of a corresponding tank xi, yi and its parameters ai and wi (0 ≤ ai ≤ 2π, 0 ≤ wi ≤ 100). Numbers ai and wi contain at most 5 digits after the decimal point. All coordinates are integers and their absolute values do not exceed 105. Enemy tanks can rotate a turret in the clockwise as well as in the counterclockwise direction at the angular speed of not more than wi. It is guaranteed that each of the enemy tanks will need at least 0.1 seconds to aim at any point of the segment AB and each of the enemy tanks is posistioned no closer than 0.1 meters to line AB. On the last line is given the number k (0 ≤ k ≤ n).

Print a single number with absolute or relative error no more than 10 - 4 — the minimum required speed of Pedalny in meters per second.


Vasya plays the Need For Brake. He plays because he was presented with a new computer wheel for birthday! Now he is sure that he will win the first place in the championship in his favourite racing computer game! n racers take part in the championship, which consists of a number of races. After each race racers are arranged from place first to n-th (no two racers share the same place) and first m places are awarded. Racer gains bi points for i-th awarded place, which are added to total points, obtained by him for previous races. It is known that current summary score of racer i is ai points. In the final standings of championship all the racers will be sorted in descending order of points. Racers with an equal amount of points are sorted by increasing of the name in lexicographical order.Unfortunately, the championship has come to an end, and there is only one race left. Vasya decided to find out what the highest and lowest place he can take up as a result of the championship.

The first line contains number n (1 ≤ n ≤ 105) — number of racers. Each of the next n lines contains si and ai — nick of the racer (nonempty string, which consist of no more than 20 lowercase Latin letters) and the racer's points (0 ≤ ai ≤ 106). Racers are given in the arbitrary order. The next line contains the number m (0 ≤ m ≤ n). Then m nonnegative integer numbers bi follow. i-th number is equal to amount of points for the i-th awarded place (0 ≤ bi ≤ 106). The last line contains Vasya's racer nick.

Output two numbers — the highest and the lowest place Vasya can take up as a result of the championship.

3
teama 10
teamb 20
teamc 40
2
10 20
teama


A stowaway and a controller play the following game. The train is represented by n wagons which are numbered with positive integers from 1 to n from the head to the tail. The stowaway and the controller are initially in some two different wagons. Every minute the train can be in one of two conditions — moving or idle. Every minute the players move.The controller's move is as follows. The controller has the movement direction — to the train's head or to its tail. During a move the controller moves to the neighbouring wagon correspondingly to its movement direction. If at the end of his move the controller enters the 1-st or the n-th wagon, that he changes the direction of his movement into the other one. In other words, the controller cyclically goes from the train's head to its tail and back again during all the time of a game, shifting during each move by one wagon. Note, that the controller always have exactly one possible move.The stowaway's move depends from the state of the train. If the train is moving, then the stowaway can shift to one of neighbouring wagons or he can stay where he is without moving. If the train is at a station and is idle, then the stowaway leaves the train (i.e. he is now not present in any train wagon) and then, if it is not the terminal train station, he enters the train again into any of n wagons (not necessarily into the one he's just left and not necessarily into the neighbouring one). If the train is idle for several minutes then each such minute the stowaway leaves the train and enters it back.Let's determine the order of the players' moves. If at the given minute the train is moving, then first the stowaway moves and then the controller does. If at this minute the train is idle, then first the stowaway leaves the train, then the controller moves and then the stowaway enters the train.If at some point in time the stowaway and the controller happen to be in one wagon, then the controller wins: he makes the stowaway pay fine. If after a while the stowaway reaches the terminal train station, then the stowaway wins: he simply leaves the station during his move and never returns there again.At any moment of time the players know each other's positions. The players play in the optimal way. Specifically, if the controller wins, then the stowaway plays so as to lose as late as possible. As all the possible moves for the controller are determined uniquely, then he is considered to play optimally always. Determine the winner.

The first line contains three integers n, m and k. They represent the number of wagons in the train, the stowaway's and the controller's initial positions correspondingly (2 ≤ n ≤ 50, 1 ≤ m, k ≤ n, m ≠ k). The second line contains the direction in which a controller moves. "to head" means that the controller moves to the train's head and "to tail" means that the controller moves to its tail. It is guaranteed that in the direction in which the controller is moving, there is at least one wagon. Wagon 1 is the head, and wagon n is the tail. The third line has the length from 1 to 200 and consists of symbols "0" and "1". The i-th symbol contains information about the train's state at the i-th minute of time. "0" means that in this very minute the train moves and "1" means that the train in this very minute stands idle. The last symbol of the third line is always "1" — that's the terminal train station.

If the stowaway wins, print "Stowaway" without quotes. Otherwise, print "Controller" again without quotes, then, separated by a space, print the number of a minute, at which the stowaway will be caught.


Let us remind you part of the rules of Codeforces. The given rules slightly simplified, use the problem statement as a formal document.In the beginning of the round the contestants are divided into rooms. Each room contains exactly n participants. During the contest the participants are suggested to solve five problems, A, B, C, D and E. For each of these problem, depending on when the given problem was solved and whether it was solved at all, the participants receive some points. Besides, a contestant can perform hacks on other contestants. For each successful hack a contestant earns 100 points, for each unsuccessful hack a contestant loses 50 points. The number of points for every contestant is represented by the sum of points he has received from all his problems, including hacks.You are suggested to determine the leader for some room; the leader is a participant who has maximum points.

The first line contains an integer n, which is the number of contestants in the room (1 ≤ n ≤ 50). The next n lines contain the participants of a given room. The i-th line has the format of "handlei plusi minusi ai bi ci di ei" — it is the handle of a contestant, the number of successful hacks, the number of unsuccessful hacks and the number of points he has received from problems A, B, C, D, E correspondingly. The handle of each participant consists of Latin letters, digits and underscores and has the length from 1 to 20 characters. There are the following limitations imposed upon the numbers:    0 ≤ plusi, minusi ≤ 50;  150 ≤ ai ≤ 500 or ai = 0, if problem A is not solved;  300 ≤ bi ≤ 1000 or bi = 0, if problem B is not solved;  450 ≤ ci ≤ 1500 or ci = 0, if problem C is not solved;  600 ≤ di ≤ 2000 or di = 0, if problem D is not solved;  750 ≤ ei ≤ 2500 or ei = 0, if problem E is not solved.  All the numbers are integer. All the participants have different handles. It is guaranteed that there is exactly one leader in the room (i.e. there are no two participants with the maximal number of points).

Print on the single line the handle of the room leader.

NoteThe number of points that each participant from the example earns, are as follows:   Petr — 3860  tourist — 4140  Egor — 4030  c00lH4x0R —  - 350  some_participant — 2220 Thus, the leader of the room is tourist.


Let's imagine: there is a chess piece billiard ball. Its movements resemble the ones of a bishop chess piece. The only difference is that when a billiard ball hits the board's border, it can reflect from it and continue moving.More formally, first one of four diagonal directions is chosen and the billiard ball moves in that direction. When it reaches the square located on the board's edge, the billiard ball reflects from it; it changes the direction of its movement by 90 degrees and continues moving. Specifically, having reached a corner square, the billiard ball is reflected twice and starts to move the opposite way. While it moves, the billiard ball can make an infinite number of reflections. At any square of its trajectory the billiard ball can stop and on that the move is considered completed.  It is considered that one billiard ball a beats another billiard ball b if a can reach a point where b is located.You are suggested to find the maximal number of billiard balls, that pairwise do not beat each other and that can be positioned on a chessboard n × m in size.

The first line contains two integers n and m (2 ≤ n, m ≤ 106).

Print a single number, the maximum possible number of billiard balls that do not pairwise beat each other. Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is preferred to use cin (also you may use the %I64d specificator).


In one very large and very respectable company there is a cloakroom with a coat hanger. It is represented by n hooks, positioned in a row. The hooks are numbered with positive integers from 1 to n from the left to the right.The company workers have a very complicated work schedule. At the beginning of a work day all the employees are not there and the coat hanger in the cloakroom is empty. At some moments of time the employees arrive and some of them leave.When some employee arrives, he hangs his cloak on one of the available hooks. To be of as little discomfort to his colleagues as possible, the hook where the coat will hang, is chosen like this. First the employee chooses the longest segment among available hooks following in a row. If there are several of such segments, then he chooses the one closest to the right. After that the coat is hung on the hook located in the middle of this segment. If the segment has an even number of hooks, then among two central hooks we choose the one closest to the right.When an employee leaves, he takes his coat. As all the company workers deeply respect each other, no one takes somebody else's coat.From time to time the director of this respectable company gets bored and he sends his secretary to see how many coats hang on the coat hanger from the i-th to the j-th hook inclusive. And this whim is always to be fulfilled, otherwise the director gets angry and has a mental breakdown.Not to spend too much time traversing from the director's office to the cloakroom and back again, the secretary asked you to write a program, emulating the company cloakroom's work.

The first line contains two integers n, q (1 ≤ n ≤ 109, 1 ≤ q ≤ 105), which are the number of hooks on the hanger and the number of requests correspondingly. Then follow q lines with requests, sorted according to time. The request of the type "0 i j" (1 ≤ i ≤ j ≤ n) — is the director's request. The input data has at least one director's request. In all other cases the request contains a positive integer not exceeding 109 — an employee identificator. Each odd appearance of the identificator of an employee in the request list is his arrival. Each even one is his leaving. All employees have distinct identificators. When any employee arrives, there is always at least one free hook.

For each director's request in the input data print a single number on a single line — the number of coats hanging on the hooks from the i-th one to the j-th one inclusive.


There is a square box 6 × 6 in size. It contains 36 chips 1 × 1 in size. Those chips contain 36 different characters — "0"-"9" and "A"-"Z". There is exactly one chip with each character.You are allowed to make the following operations: you may choose one of 6 rows or one of 6 columns and cyclically shift the chips there to one position to the left or to the right (for the row) or upwards or downwards (for the column). Those operations are allowed to perform several times. To solve the puzzle is to shift the chips using the above described operations so that they were written in the increasing order (exactly equal to the right picture). An example of solving the puzzle is shown on a picture below.  Write a program that finds the sequence of operations that solves the puzzle. That sequence should not necessarily be shortest, but you should not exceed the limit of 10000 operations. It is guaranteed that the solution always exists.

The input data are represented by 6 lines containing 6 characters each. They are the puzzle's initial position. Those lines contain each character from the string "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" exactly once.

On the first line print number n, which is the number of operations. On the next n lines print the sequence of operations one per line. An operation is described by a word consisting of two characters. The first character shows the direction where the row or the column will be shifted. The possible directions are "L", "R" (to the left, to the right correspondingly, we shift a row), "U", "D" (upwards, downwards correspondingly, we shift a column). The second character is the number of the row (or the column), it is an integer from "1" to "6". The rows are numbered from the top to the bottom, the columns are numbered from the left to the right. The number of operations should not exceed 104. If there are several solutions, print any of them.

01W345
729AB6
CD8FGH
IJELMN
OPKRST
UVQXYZ


Facetook is a well known social network website, and it will launch a new feature called Facetook Priority Wall. This feature will sort all posts from your friends according to the priority factor (it will be described).This priority factor will be affected by three types of actions:   1. "X posted on Y's wall" (15 points),  2. "X commented on Y's post" (10 points),  3. "X likes Y's post" (5 points). X and Y will be two distinct names. And each action will increase the priority factor between X and Y (and vice versa) by the above value of points (the priority factor between X and Y is the same as the priority factor between Y and X).You will be given n actions with the above format (without the action number and the number of points), and you have to print all the distinct names in these actions sorted according to the priority factor with you.

The first line contains your name. The second line contains an integer n, which is the number of actions (1 ≤ n ≤ 100). Then n lines follow, it is guaranteed that each one contains exactly 1 action in the format given above. There is exactly one space between each two words in a line, and there are no extra spaces. All the letters are lowercase. All names in the input will consist of at least 1 letter and at most 10 small Latin letters.

Print m lines, where m is the number of distinct names in the input (excluding yourself). Each line should contain just 1 name. The names should be sorted according to the priority factor with you in the descending order (the highest priority factor should come first). If two or more names have the same priority factor, print them in the alphabetical (lexicographical) order. Note, that you should output all the names that are present in the input data (excluding yourself), even if that person has a zero priority factor. The lexicographical comparison is performed by the standard "<" operator in modern programming languages. The line a is lexicographically smaller than the line b, if either a is the prefix of b, or if exists such an i (1 ≤ i ≤ min(|a|, |b|)), that ai < bi, and for any j (1 ≤ j < i) aj = bj, where |a| and |b| stand for the lengths of strings a and b correspondently.

ahmed
3
ahmed posted on fatma's wall
fatma commented on ahmed's post
mona likes ahmed's post


Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.A common divisor for two positive numbers is a number which both numbers are divisible by.But your teacher wants to give you a harder task, in this task you have to find the greatest common divisor d between two integers a and b that is in a given range from low to high (inclusive), i.e. low ≤ d ≤ high. It is possible that there is no common divisor in the given range.You will be given the two integers a and b, then n queries. Each query is a range from low to high and you have to answer each query.

The first line contains two integers a and b, the two integers as described above (1 ≤ a, b ≤ 109). The second line contains one integer n, the number of queries (1 ≤ n ≤ 104). Then n lines follow, each line contains one query consisting of two integers, low and high (1 ≤ low ≤ high ≤ 109).

Print n lines. The i-th of them should contain the result of the i-th query in the input. If there is no common divisor in the given range for any query, you should print -1 as a result for this query.


Ahmed and Mostafa used to compete together in many programming contests for several years. Their coach Fegla asked them to solve one challenging problem, of course Ahmed was able to solve it but Mostafa couldn't.This problem is similar to a standard problem but it has a different format and constraints.In the standard problem you are given an array of integers, and you have to find one or more consecutive elements in this array where their sum is the maximum possible sum.But in this problem you are given n small arrays, and you will create one big array from the concatenation of one or more instances of the small arrays (each small array could occur more than once). The big array will be given as an array of indexes (1-based) of the small arrays, and the concatenation should be done in the same order as in this array. Then you should apply the standard problem mentioned above on the resulting big array.For example let's suppose that the small arrays are {1, 6, -2}, {3, 3} and {-5, 1}. And the indexes in the big array are {2, 3, 1, 3}. So the actual values in the big array after formatting it as concatenation of the small arrays will be {3, 3, -5, 1, 1, 6, -2, -5, 1}. In this example the maximum sum is 9.Can you help Mostafa solve this problem?

The first line contains two integers n and m, n is the number of the small arrays (1 ≤ n ≤ 50), and m is the number of indexes in the big array (1 ≤ m ≤ 250000). Then follow n lines, the i-th line starts with one integer l which is the size of the i-th array (1 ≤ l ≤ 5000), followed by l integers each one will be greater than or equal -1000 and less than or equal 1000. The last line contains m integers which are the indexes in the big array, and you should concatenate the small arrays in the same order, and each index will be greater than or equal to 1 and less than or equal to n. The small arrays are numbered from 1 to n in the same order as given in the input. Some of the given small arrays may not be used in big array. Note, that the array is very big. So if you try to build it straightforwardly, you will probably get time or/and memory limit exceeded.

Print one line containing the maximum sum in the big array after formatting it as described above. You must choose at least one element for the sum, i. e. it cannot be empty. Please, do not use %lld specificator to write 64-bit integers in C++. It is preferred to use cout (also you may use %I64d).


You have got a new job, and it's very interesting, you are a ship captain. Your first task is to move your ship from one point to another point, and for sure you want to move it at the minimum cost.And it's well known that the shortest distance between any 2 points is the length of the line segment between these 2 points. But unfortunately there is an island in the sea, so sometimes you won't be able to move your ship in the line segment between the 2 points.You can only move to safe points. A point is called safe if it's on the line segment between the start and end points, or if it's on the island's edge.But you are too lucky, you have got some clever and strong workers and they can help you in your trip, they can help you move the ship in the sea and they will take 1 Egyptian pound for each moving unit in the sea, and they can carry the ship (yes, they are very strong) and walk on the island and they will take 2 Egyptian pounds for each moving unit in the island. The money which you will give to them will be divided between all workers, so the number of workers does not matter here.You can move your ship on the island edge, and it will be considered moving in the sea.Now you have a sea map, and you have to decide what is the minimum cost for your trip.Your starting point is (xStart, yStart), and the end point is (xEnd, yEnd), both points will be different.The island will be a convex polygon and there will be no more than 2 polygon points on the same line, also the starting and the end points won't be inside or on the boundary of the island. The points for the polygon will be given in the anti-clockwise order.

The first line contains 4 integers, xStart, yStart, xEnd and yEnd ( - 100 ≤ xStart, yStart, xEnd, yEnd ≤ 100). The second line contains an integer n, which is the number of points in the polygon (3 ≤ n ≤ 30), followed by a line containing n pairs of integers x and y, which are the coordinates of the points ( - 100 ≤ x, y ≤ 100), the polygon points will be distinct.

Print one line which contains the minimum possible cost. The absolute or relative error in the answer should not exceed 10 - 6.


Can you imagine our life if we removed all zeros from it? For sure we will have many problems.In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation a + b = c, where a and b are positive integers, and c is the sum of a and b. Now let's remove all zeros from this equation. Will the equation remain correct after removing all zeros?For example if the equation is 101 + 102 = 203, if we removed all zeros it will be 11 + 12 = 23 which is still a correct equation.But if the equation is 105 + 106 = 211, if we removed all zeros it will be 15 + 16 = 211 which is not a correct equation.

The input will consist of two lines, the first line will contain the integer a, and the second line will contain the integer b which are in the equation as described above (1 ≤ a, b ≤ 109). There won't be any leading zeros in both. The value of c should be calculated as c = a + b.

The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise.


The kingdom of Olympia consists of N cities and M bidirectional roads. Each road connects exactly two cities and two cities can be connected with more than one road. Also it possible that some roads connect city with itself making a loop.All roads are constantly plundered with bandits. After a while bandits became bored of wasting time in road robberies, so they suggested the king of Olympia to pay off. According to the offer, bandits want to get a gift consisted of gold and silver coins. Offer also contains a list of restrictions: for each road it is known gi — the smallest amount of gold and si — the smallest amount of silver coins that should be in the gift to stop robberies on the road. That is, if the gift contains a gold and b silver coins, then bandits will stop robberies on all the roads that gi ≤ a and si ≤ b.Unfortunately kingdom treasury doesn't contain neither gold nor silver coins, but there are Olympian tugriks in it. The cost of one gold coin in tugriks is G, and the cost of one silver coin in tugriks is S. King really wants to send bandits such gift that for any two cities there will exist a safe path between them. Your task is to find the minimal cost in Olympian tugriks of the required gift.

The first line of the input contains two integers N and M (2 ≤ N ≤ 200, 1 ≤ M ≤ 50 000) — the number of cities and the number of roads, respectively. The second line contains two integers G and S (1 ≤ G, S ≤ 109) — the prices of gold and silver coins in tugriks. The following M lines contain information about the offer. Each of the records in list is given as four integers xi, yi, gi, si, where xi and yi are the numbers of cities that the road connects and gi, si are minimal gold and silver coins requirements for the i-th road (1 ≤ xi, yi ≤ N, 1 ≤ gi, si ≤ 109). Cities are numbered from 1 to N. It is possible that there are more than one road between a pair of cities. It is possible that a road connects the city with itself.

The output should contain the minimal cost of the gift in Olympian tugriks. If there is no gift that satisfies the given requirements output .


Modern researches has shown that a flock of hungry mice searching for a piece of cheese acts as follows: if there are several pieces of cheese then each mouse chooses the closest one. After that all mice start moving towards the chosen piece of cheese. When a mouse or several mice achieve the destination point and there is still a piece of cheese in it, they eat it and become well-fed. Each mice that reaches this point after that remains hungry. Moving speeds of all mice are equal.If there are several ways to choose closest pieces then mice will choose it in a way that would minimize the number of hungry mice. To check this theory scientists decided to conduct an experiment. They located N mice and M pieces of cheese on a cartesian plane where all mice are located on the line y = Y0 and all pieces of cheese — on another line y = Y1. To check the results of the experiment the scientists need a program which simulates the behavior of a flock of hungry mice.Write a program that computes the minimal number of mice which will remain hungry, i.e. without cheese.

The first line of the input contains four integer numbers N (1 ≤ N ≤ 105), M (0 ≤ M ≤ 105), Y0 (0 ≤ Y0 ≤ 107), Y1 (0 ≤ Y1 ≤ 107, Y0 ≠ Y1). The second line contains a strictly increasing sequence of N numbers — x coordinates of mice. Third line contains a strictly increasing sequence of M numbers — x coordinates of cheese. All coordinates are integers and do not exceed 107 by absolute value.

The only line of output should contain one number — the minimal number of mice which will remain without cheese.

NoteAll the three mice will choose the first piece of cheese. Second and third mice will eat this piece. The first one will remain hungry, because it was running towards the same piece, but it was late. The second piece of cheese will remain uneaten.


Scientists of planet Olympia are conducting an experiment in mutation of primitive organisms. Genome of organism from this planet can be represented as a string of the first K capital English letters. For each pair of types of genes they assigned ai, j — a risk of disease occurence in the organism provided that genes of these types are adjacent in the genome, where i — the 1-based index of the first gene and j — the index of the second gene. The gene 'A' has index 1, 'B' has index 2 and so on. For example, a3, 2 stands for the risk of 'CB' fragment. Risk of disease occurence in the organism is equal to the sum of risks for each pair of adjacent genes in the genome.Scientists have already obtained a base organism. Some new organisms can be obtained by mutation of this organism. Mutation involves removal of all genes of some particular types. Such removal increases the total risk of disease occurence additionally. For each type of genes scientists determined ti — the increasement of the total risk of disease occurence provided by removal of all genes having type with index i. For example, t4 stands for the value of additional total risk increasement in case of removing all the 'D' genes.Scientists want to find a number of different organisms that can be obtained from the given one which have the total risk of disease occurence not greater than T. They can use only the process of mutation described above. Two organisms are considered different if strings representing their genomes are different. Genome should contain at least one gene.

The first line of the input contains three integer numbers N (1 ≤ N ≤ 200 000) — length of the genome of base organism, K (1 ≤ K ≤ 22) — the maximal index of gene type in the genome and T (1 ≤ T ≤ 2·109) — maximal allowable risk of disease occurence. The second line contains the genome of the given organism. It is a string of the first K capital English letters having length N. The third line contains K numbers t1, t2, ..., tK, where ti is additional risk value of disease occurence provided by removing of all genes of the i-th type. The following K lines contain the elements of the given matrix ai, j. The i-th line contains K numbers. The j-th number of the i-th line stands for a risk of disease occurence for the pair of genes, first of which corresponds to the i-th letter and second of which corresponds to the j-th letter. The given matrix is not necessarily symmetrical. All the numbers in the input are integer, non-negative and all of them except T are not greater than 109. It is guaranteed that the maximal possible risk of organism that can be obtained from the given organism is strictly smaller than 231.

Output the number of organisms that can be obtained from the base one and which have the total risk of disease occurence not greater than T.

NoteExplanation: one can obtain the following organisms (risks are stated in brackets): BACAC (11), ACAC (10), BAA (5), B (6), AA (4).


Bitwise exclusive OR (or bitwise addition modulo two) is a binary operation which is equivalent to applying logical exclusive OR to every pair of bits located on the same positions in binary notation of operands. In other words, a binary digit of the result is equal to 1 if and only if bits on the respective positions in the operands are different.For example, if X = 10910 = 11011012, Y = 4110 = 1010012, then:  X xor Y  =  6810  =  10001002. Write a program, which takes two non-negative integers A and B as an input and finds two non-negative integers X and Y, which satisfy the following conditions:   A = X + Y  B  =  X xor Y, where xor is bitwise exclusive or.  X is the smallest number among all numbers for which the first two conditions are true.

The first line contains integer number A and the second line contains integer number B (0 ≤ A, B ≤ 264 - 1).

The only output line should contain two integer non-negative numbers X and Y. Print the only number -1 if there is no answer.


Tourist walks along the X axis. He can choose either of two directions and any speed not exceeding V. He can also stand without moving anywhere. He knows from newspapers that at time t1 in the point with coordinate x1 an interesting event will occur, at time t2 in the point with coordinate x2 — another one, and so on up to (xn, tn). Interesting events are short so we can assume they are immediate. Event i counts visited if at time ti tourist was at point with coordinate xi.Write program tourist that will find maximum number of events tourist if:   at the beginning (when time is equal to 0) tourist appears at point 0,  tourist can choose initial point for himself. Yes, you should answer on two similar but different questions.

The first line of input contains single integer number N (1 ≤ N ≤ 100000) — number of interesting events. The following N lines contain two integers xi and ti — coordinate and time of the i-th event. The last line of the input contains integer V — maximum speed of the tourist. All xi will be within range  - 2·108 ≤ xi ≤ 2·108, all ti will be between 1 and 2·106 inclusive. V will be positive and will not exceed 1000. The input may contain events that happen at the same time or in the same place but not in the same place at the same time.

The only line of the output should contain two space-sepatated integers — maximum number of events tourist can visit in he starts moving from point 0 at time 0, and maximum number of events tourist can visit if he chooses the initial point for himself.


You are given N points on a plane. Write a program which will find the sum of squares of distances between all pairs of points.

The first line of input contains one integer number N (1 ≤ N ≤ 100 000) — the number of points. Each of the following N lines contain two integer numbers X and Y ( - 10 000 ≤ X, Y ≤ 10 000) — the coordinates of points. Two or more points may coincide.

The only line of output should contain the required sum of squares of distances between all pairs of points.


For some reason in many American cartoons anvils fall from time to time onto heroes' heads. Of course, safes, wardrobes, cruisers, planes fall sometimes too... But anvils do so most of all.Anvils come in different sizes and shapes. Quite often they get the hero stuck deep in the ground. But have you ever thought who throws anvils from the sky? From what height? We are sure that such questions have never troubled you!It turns out that throwing an anvil properly is not an easy task at all. Let's describe one of the most popular anvil throwing models.Let the height p of the potential victim vary in the range [0;a] and the direction of the wind q vary in the range [ - b;b]. p and q could be any real (floating) numbers. Then we can assume that the anvil will fit the toon's head perfectly only if the following equation has at least one real root:   Determine the probability with which an aim can be successfully hit by an anvil.You can assume that the p and q coefficients are chosen equiprobably and independently in their ranges.

The first line contains integer t (1 ≤ t ≤ 10000) — amount of testcases. Each of the following t lines contain two space-separated integers a and b (0 ≤ a, b ≤ 106). Pretests contain all the tests with 0 < a < 10, 0 ≤ b < 10.

Print t lines — the probability of a successful anvil hit for each testcase. The absolute or relative error of the answer should not exceed 10 - 6.


"Eat a beaver, save a tree!" — That will be the motto of ecologists' urgent meeting in Beaverley Hills.And the whole point is that the population of beavers on the Earth has reached incredible sizes! Each day their number increases in several times and they don't even realize how much their unhealthy obsession with trees harms the nature and the humankind. The amount of oxygen in the atmosphere has dropped to 17 per cent and, as the best minds of the world think, that is not the end.In the middle of the 50-s of the previous century a group of soviet scientists succeed in foreseeing the situation with beavers and worked out a secret technology to clean territory. The technology bears a mysterious title "Beavermuncher-0xFF". Now the fate of the planet lies on the fragile shoulders of a small group of people who has dedicated their lives to science.The prototype is ready, you now need to urgently carry out its experiments in practice. You are given a tree, completely occupied by beavers. A tree is a connected undirected graph without cycles. The tree consists of n vertices, the i-th vertex contains ki beavers. "Beavermuncher-0xFF" works by the following principle: being at some vertex u, it can go to the vertex v, if they are connected by an edge, and eat exactly one beaver located at the vertex v. It is impossible to move to the vertex v if there are no beavers left in v. "Beavermuncher-0xFF" cannot just stand at some vertex and eat beavers in it. "Beavermuncher-0xFF" must move without stops.Why does the "Beavermuncher-0xFF" works like this? Because the developers have not provided place for the battery in it and eating beavers is necessary for converting their mass into pure energy.It is guaranteed that the beavers will be shocked by what is happening, which is why they will not be able to move from a vertex of the tree to another one. As for the "Beavermuncher-0xFF", it can move along each edge in both directions while conditions described above are fulfilled.The root of the tree is located at the vertex s. This means that the "Beavermuncher-0xFF" begins its mission at the vertex s and it must return there at the end of experiment, because no one is going to take it down from a high place. Determine the maximum number of beavers "Beavermuncher-0xFF" can eat and return to the starting vertex.

The first line contains integer n — the number of vertices in the tree (1 ≤ n ≤ 105). The second line contains n integers ki (1 ≤ ki ≤ 105) — amounts of beavers on corresponding vertices. Following n - 1 lines describe the tree. Each line contains two integers separated by space. These integers represent two vertices connected by an edge. Vertices are numbered from 1 to n. The last line contains integer s — the number of the starting vertex (1 ≤ s ≤ n).

Print the maximum number of beavers munched by the "Beavermuncher-0xFF". Please, do not use %lld specificator to write 64-bit integers in C++. It is preferred to use cout (also you may use %I64d).


...Mike the TV greets you again! Tired of the monotonous furniture? Sick of gray routine? Dreaming about dizzying changes in your humble abode? We have something to offer you! This domino carpet for only $99.99 will change your life! You can lay it on the floor, hang it on the wall or even on the ceiling! Among other things ... Having watched the commercial, virus Hexadecimal also wanted to get a Domino Carpet and wanted badly to be photographed in front of it. But of course, a virus will never consent to buying a licensed Carpet! So she ordered a truck of dominoes and decided to make such a Carpet herself. The original Domino Carpet is a field of squares n × m in size. Each square is half of a domino, and can be rotated either vertically or horizontally, independently from its neighbors. Vertically rotated domino halves look like this:    And horizontally rotated halves look like this:   Notice, that some halves looks the same in both rotations, but other halves differ.Dominoes bought by Hexadecimal are represented by uncuttable chips 1 × 2 in size, which can be laid either vertically or horizontally. If the chip is laid vertically, then both of it's halves should be laid vertically orientated; if the chip is laid horizontally, then both of it's halves should be laid horizontally.The samples of valid and invalid dominoes laid vertically and horizontally are:    Virus Hexadecimal assembles her own Domino Carpet so that the following conditions are satisfied:  each carpet square is covered by a domino chip, i.e. there are no empty squares;  all domino chips lie entirely within the carpet and don't overlap with each other;  if there is a horizontal domino chip with its left half in column j then there are no horizontal domino chips with their left halves in columns j - 1 or j + 1. Before starting to assemble her own Domino Carpet, the virus wants to know the number of ways to achieve the intended purpose modulo 109 + 7.You can assume that the virus has an infinitely large number of dominoes of each type.

The first line contains two integers n and m, separated by a space — the size of the Domino Carpet (1 ≤ n, m ≤ 250). Next 4n + 1 lines contain 4m + 1 symbols.  Each square of the Domino Carpet, which is a domino half, is described by a 3 × 3 square. Symbol 'O' in this square indicates the presence of a point, symbol '.' — its absence.  Each 3 × 3 square is delineated from adjacent squares by symbols '#' as shown in the examples.  It is guaranteed that every box describes the correct half of a domino.  In all pretests the Domino Carpets have the size of 2 × 2 and 4 × 4.

Print a single number, the number of ways to assemble the Domino Carpet modulo 109 + 7, using only standard dominoes of size 1 × 2.

NoteA note to the first example: all correct ways to make Domino Carpet are represented below:  And this way is incorrect:


The year of 2012 is coming...According to an ancient choradrican legend in this very year, in 2012, Diablo and his brothers Mephisto and Baal will escape from hell, and innumerable hordes of demons will enslave the human world. But seven brave heroes have already gathered on the top of a mountain Arreat to protect us mere mortals from the effect of this terrible evil.The seven great heroes are: amazon Anka, barbarian Chapay, sorceress Cleo, druid Troll, necromancer Dracul, paladin Snowy and a professional hit girl Hexadecimal. Heroes already know how much experience will be given for each of the three megabosses: a for Mephisto, b for Diablo and c for Baal.Here's the problem: heroes are as much as seven and megabosses are only three! Then our heroes decided to split into three teams, where each team will go to destroy their own megaboss. Each team member will receive a  of experience, rounded down, where x will be the amount of experience for the killed megaboss and y — the number of people in the team.Heroes do not want to hurt each other's feelings, so they want to split into teams so that the difference between the hero who received the maximum number of experience and the hero who received the minimum number of experience were minimal. Since there can be several divisions into teams, then you need to find the one in which the total amount of liking in teams were maximum.It is known that some heroes like others. But if hero p likes hero q, this does not mean that the hero q likes hero p. No hero likes himself.The total amount of liking in teams is the amount of ordered pairs (p, q), such that heroes p and q are in the same group, and hero p likes hero q (but it is not important if hero q likes hero p). In case of heroes p and q likes each other and they are in the same group, this pair should be counted twice, as (p, q) and (q, p).A team can consist even of a single hero, but it is important that every megaboss was destroyed. All heroes must be involved in the campaign against evil. None of the heroes can be in more than one team.It is guaranteed that every hero is able to destroy any megaboss alone.

The first line contains a single non-negative integer n (0 ≤ n ≤ 42) — amount of liking between the heroes. Next n lines describe liking in the form "p likes q", meaning that the hero p likes the hero q (p  ≠  q). Every liking is described in the input exactly once, no hero likes himself. In the last line are given three integers a, b and c (1 ≤ a, b, c ≤ 2·109), separated by spaces: the experience for Mephisto, the experience for Diablo and experience for Baal. In all the pretests, except for examples from the statement, the following condition is satisfied: a = b = c.

Print two integers — the minimal difference in the experience between two heroes who will receive the maximum and minimum number of experience points, and the maximal total amount of liking in teams (the number of friendships between heroes that end up in one team). When calculating the second answer, the team division should satisfy the difference-minimizing contraint. I.e. primary you should minimize the difference in the experience and secondary you should maximize the total amount of liking.

NoteA note to first example: it the first team should be Dracul, Troll and Anka, in the second one Hexadecimal and Snowy, and in the third Cleo и Chapay.

3
Troll likes Dracul
Dracul likes Anka
Snowy likes Hexadecimal
210 200 180

2
Anka likes Chapay
Chapay likes Anka
10000 50 50


Have you ever tasted Martian food? Well, you should.Their signature dish is served on a completely black plate with the radius of R, flat as a pancake.First, they put a perfectly circular portion of the Golden Honduras on the plate. It has the radius of r and is located as close to the edge of the plate as possible staying entirely within the plate. I. e. Golden Honduras touches the edge of the plate from the inside. It is believed that the proximity of the portion of the Golden Honduras to the edge of a plate demonstrates the neatness and exactness of the Martians.Then a perfectly round portion of Pink Guadeloupe is put on the plate. The Guadeloupe should not overlap with Honduras, should not go beyond the border of the plate, but should have the maximum radius. I. e. Pink Guadeloupe should touch the edge of the plate from the inside, and touch Golden Honduras from the outside. For it is the size of the Rose Guadeloupe that shows the generosity and the hospitality of the Martians.Further, the first portion (of the same perfectly round shape) of Green Bull Terrier is put on the plate. It should come in contact with Honduras and Guadeloupe, should not go beyond the border of the plate and should have maximum radius.Each of the following portions of the Green Bull Terrier must necessarily touch the Golden Honduras, the previous portion of the Green Bull Terrier and touch the edge of a plate, but should not go beyond the border.To determine whether a stranger is worthy to touch the food, the Martians ask him to find the radius of the k-th portion of the Green Bull Terrier knowing the radii of a plate and a portion of the Golden Honduras. And are you worthy?

The first line contains integer t (1 ≤ t ≤ 104) — amount of testcases. Each of the following t lines contain three positive integers: the radii of the plate and a portion of the Golden Honduras R and r (1 ≤ r < R ≤ 104) and the number k (1 ≤ k ≤ 104). In the pretests 1 ≤ k ≤ 2.

Print t lines — the radius of the k-th portion of the Green Bull Terrier for each test. The absolute or relative error of the answer should not exceed 10 - 6.

NoteDish from the first sample looks like this:Dish from the second sample looks like this:


The Easter Rabbit laid n eggs in a circle and is about to paint them. Each egg should be painted one color out of 7: red, orange, yellow, green, blue, indigo or violet. Also, the following conditions should be satisfied:  Each of the seven colors should be used to paint at least one egg.  Any four eggs lying sequentially should be painted different colors. Help the Easter Rabbit paint the eggs in the required manner. We know that it is always possible.

The only line contains an integer n — the amount of eggs (7 ≤ n ≤ 100).

Print one line consisting of n characters. The i-th character should describe the color of the i-th egg in the order they lie in the circle. The colors should be represented as follows: "R" stands for red, "O" stands for orange, "Y" stands for yellow, "G" stands for green, "B" stands for blue, "I" stands for indigo, "V" stands for violet. If there are several answers, print any of them.

NoteThe way the eggs will be painted in the first sample is shown on the picture:


Haiku is a genre of Japanese traditional poetry.A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".Three phases from a certain poem are given. Determine whether it is haiku or not.

The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The i-th line contains the i-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification.

Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes).

on  codeforces
beta round is running
   a rustling of keys

how many gallons
of edo s rain did you drink
                                cuckoo


Two beavers, Timur and Marsel, play the following game.There are n logs, each of exactly m meters in length. The beavers move in turns. For each move a beaver chooses a log and gnaws it into some number (more than one) of equal parts, the length of each one is expressed by an integer and is no less than k meters. Each resulting part is also a log which can be gnawed in future by any beaver. The beaver that can't make a move loses. Thus, the other beaver wins.Timur makes the first move. The players play in the optimal way. Determine the winner.

The first line contains three integers n, m, k (1 ≤ n, m, k ≤ 109).

Print "Timur", if Timur wins, or "Marsel", if Marsel wins. You should print everything without the quotes.

NoteIn the first sample the beavers only have one log, of 15 meters in length. Timur moves first. The only move he can do is to split the log into 3 parts each 5 meters in length. Then Marsel moves but he can't split any of the resulting logs, as k = 4. Thus, the winner is Timur.In the second example the beavers have 4 logs 9 meters in length. Timur can't split any of them, so that the resulting parts possessed the length of not less than 5 meters, that's why he loses instantly.


After Fox Ciel won an onsite round of a programming contest, she took a bus to return to her castle. The fee of the bus was 220 yen. She met Rabbit Hanako in the bus. They decided to play the following game because they got bored in the bus.  Initially, there is a pile that contains x 100-yen coins and y 10-yen coins.  They take turns alternatively. Ciel takes the first turn.  In each turn, they must take exactly 220 yen from the pile. In Ciel's turn, if there are multiple ways to take 220 yen, she will choose the way that contains the maximal number of 100-yen coins. In Hanako's turn, if there are multiple ways to take 220 yen, she will choose the way that contains the maximal number of 10-yen coins.  If Ciel or Hanako can't take exactly 220 yen from the pile, she loses.  Determine the winner of the game.

The first line contains two integers x (0 ≤ x ≤ 106) and y (0 ≤ y ≤ 106), separated by a single space.

If Ciel wins, print "Ciel". Otherwise, print "Hanako".

NoteIn the first turn (Ciel's turn), she will choose 2 100-yen coins and 2 10-yen coins. In the second turn (Hanako's turn), she will choose 1 100-yen coin and 12 10-yen coins. In the third turn (Ciel's turn), she can't pay exactly 220 yen, so Ciel will lose.


A breakthrough among computer games, "Civilization XIII", is striking in its scale and elaborate details. Let's take a closer look at one of them.The playing area in the game is split into congruent cells that are regular hexagons. The side of each cell is equal to 1. Each unit occupies exactly one cell of the playing field. The field can be considered infinite. Let's take a look at the battle unit called an "Archer". Each archer has a parameter "shot range". It's a positive integer that determines the radius of the circle in which the archer can hit a target. The center of the circle coincides with the center of the cell in which the archer stays. A cell is considered to be under the archer’s fire if and only if all points of this cell, including border points are located inside the circle or on its border.The picture below shows the borders for shot ranges equal to 3, 4 and 5. The archer is depicted as A.   Find the number of cells that are under fire for some archer.

The first and only line of input contains a single positive integer k — the archer's shot range (1 ≤ k ≤ 106).

Print the single number, the number of cells that are under fire. Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cout stream (also you may use the %I64d specificator).


They've screwed something up yet again... In one nuclear reactor of a research station an uncontrolled reaction is in progress and explosion which will destroy the whole station will happen soon.The station is represented by a square n × n divided into 1 × 1 blocks. Each block is either a reactor or a laboratory. There can be several reactors and exactly one of them will explode soon. The reactors can be considered impassable blocks, but one can move through laboratories. Between any two laboratories, which are in adjacent blocks, there is a corridor. Blocks are considered adjacent if they have a common edge.In each laboratory there is some number of scientists and some number of rescue capsules. Once the scientist climbs into a capsule, he is considered to be saved. Each capsule has room for not more than one scientist.The reactor, which is about to explode, is damaged and a toxic coolant trickles from it into the neighboring blocks. The block, which contains the reactor, is considered infected. Every minute the coolant spreads over the laboratories through corridors. If at some moment one of the blocks is infected, then the next minute all the neighboring laboratories also become infected. Once a lab is infected, all the scientists there that are not in rescue capsules die. The coolant does not spread through reactor blocks.There are exactly t minutes to the explosion. Any scientist in a minute can move down the corridor to the next lab, if it is not infected. On any corridor an unlimited number of scientists can simultaneously move in both directions. It is believed that the scientists inside a lab moves without consuming time. Moreover, any scientist could get into the rescue capsule instantly. It is also believed that any scientist at any given moment always has the time to perform their actions (move from the given laboratory into the next one, or climb into the rescue capsule) before the laboratory will be infected.Find the maximum number of scientists who will be able to escape.

The first line contains two integers n and t (2 ≤ n ≤ 10, 1 ≤ t ≤ 60). Each of the next n lines contains n characters. These lines describe the scientists' locations. Then exactly one empty line follows. Each of the next n more lines contains n characters. These lines describe the rescue capsules' locations. In the description of the scientists' and the rescue capsules' locations the character "Y" stands for a properly functioning reactor, "Z" stands for the malfunctioning reactor. The reactors' positions in both descriptions coincide. There is exactly one malfunctioning reactor on the station. The digits "0" - "9" stand for the laboratories. In the description of the scientists' locations those numbers stand for the number of scientists in the corresponding laboratories. In the rescue capsules' descriptions they stand for the number of such capsules in each laboratory.

Print a single number — the maximum number of scientists who will manage to save themselves.

NoteIn the second sample the events could take place as follows:


Fox Ciel safely returned to her castle, but there was something wrong with the security system of the castle: sensors attached in the castle were covering her.Ciel is at point (1, 1) of the castle now, and wants to move to point (n, n), which is the position of her room. By one step, Ciel can move from point (x, y) to either (x + 1, y) (rightward) or (x, y + 1) (upward).In her castle, c2 sensors are set at points (a + i, b + j) (for every integer i and j such that: 0 ≤ i < c, 0 ≤ j < c).Each sensor has a count value and decreases its count value every time Ciel moves. Initially, the count value of each sensor is t. Every time Ciel moves to point (x, y), the count value of a sensor at point (u, v) decreases by (|u - x| + |v - y|). When the count value of some sensor becomes strictly less than 0, the sensor will catch Ciel as a suspicious individual!Determine whether Ciel can move from (1, 1) to (n, n) without being caught by a sensor, and if it is possible, output her steps. Assume that Ciel can move to every point even if there is a censor on the point.

In the first line there are five integers n, t, a, b, c (2 ≤ n ≤ 2·105,  0 ≤ t ≤ 1014,  1 ≤ a ≤ n - c + 1,  1 ≤ b ≤ n - c + 1,  1 ≤ c ≤ n). Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin stream (also you may use the %I64d specificator).

If Ciel's objective is possible, output in first line 2n - 2 characters that represent her feasible steps, where i-th character is R if i-th step is moving rightward, or U if moving upward. If there are several solution, output lexicographically first one. Character R is lexicographically earlier than the character U. If her objective is impossible, output Impossible.

NoteThe answers for the first sample and the second sample are shown on the picture:    Here, a red point represents a point that contains a sensor.

RRUURURU URUR Impossible RRRRRRRRRRRRRRRRUUUUURUUUUURRUUUUUUUUU


After Fox Ciel got off a bus, she found that the bus she was on was a wrong bus and she lost her way in a strange town. However, she fortunately met her friend Beaver Taro and asked which way to go to her castle. Taro's response to her was a string s, and she tried to remember the string s correctly.However, Ciel feels n strings b1, b2, ... , bn are really boring, and unfortunately she dislikes to remember a string that contains a boring substring. To make the thing worse, what she can remember is only the contiguous substring of s.Determine the longest contiguous substring of s that does not contain any boring string, so that she can remember the longest part of Taro's response.

In the first line there is a string s. The length of s will be between 1 and 105, inclusive. In the second line there is a single integer n (1 ≤ n ≤ 10).  Next n lines, there is a string bi (1 ≤ i ≤ n). Each length of bi will be between 1 and 10, inclusive. Each character of the given strings will be either a English alphabet (both lowercase and uppercase) or a underscore ('_') or a digit. Assume that these strings are case-sensitive.

Output in the first line two space-separated integers len and pos: the length of the longest contiguous substring of s that does not contain any bi, and the first position of the substring (0-indexed). The position pos must be between 0 and |s| - len inclusive, where |s| is the length of string s. If there are several solutions, output any.

NoteIn the first sample, the solution is traight_alon.In the second sample, the solution is an empty string, so the output can be «0 0», «0 1», «0 2», and so on.In the third sample, the solution is either nagio or oisii.

Go_straight_along_this_street
5
str
long
tree
biginteger
ellipse


Finally Fox Ciel arrived in front of her castle!She have to type a password to enter her castle. An input device attached to her castle is a bit unusual.The input device is a 1 × n rectangle divided into n square panels. They are numbered 1 to n from left to right. Each panel has a state either ON or OFF. Initially all panels are in the OFF state. She can enter her castle if and only if x1-th, x2-th, ..., xk-th panels are in the ON state and other panels are in the OFF state.She is given an array a1, ..., al. In each move, she can perform the following operation: choose an index i (1 ≤ i ≤ l), choose consecutive ai panels, and flip the states of those panels (i.e. ON → OFF, OFF → ON).Unfortunately she forgets how to type the password with only above operations. Determine the minimal number of operations required to enter her castle.

The first line contains three integers n, k and l (1 ≤ n ≤ 10000, 1 ≤ k ≤ 10, 1 ≤ l ≤ 100), separated by single spaces. The second line contains k integers x1, ..., xk (1 ≤ x1 < x2 < ... < xk ≤ n), separated by single spaces. The third line contains l integers a1, ..., al (1 ≤ ai ≤ n), separated by single spaces. It is possible that some elements of the array ai are equal value.

Print the minimal number of moves required to type the password. If it's impossible, print -1.

NoteOne possible way to type the password in the first example is following: In the first move, choose 1st, 2nd, 3rd panels and flip those panels. In the second move, choose 5th, 6th, 7th, 8th, 9th panels and flip those panels.


Fox Ciel saw a large field while she was on a bus. The field was a n × m rectangle divided into 1 × 1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes. After seeing the field carefully, Ciel found that the crop plants of each cell were planted in following procedure:  Assume that the rows are numbered 1 to n from top to bottom and the columns are numbered 1 to m from left to right, and a cell in row i and column j is represented as (i, j).  First, each field is either cultivated or waste. Crop plants will be planted in the cultivated cells in the order of (1, 1) → ... → (1, m) → (2, 1) → ... → (2, m) → ... → (n, 1) → ... → (n, m). Waste cells will be ignored.  Crop plants (either carrots or kiwis or grapes) will be planted in each cell one after another cyclically. Carrots will be planted in the first cell, then kiwis in the second one, grapes in the third one, carrots in the forth one, kiwis in the fifth one, and so on. The following figure will show you the example of this procedure. Here, a white square represents a cultivated cell, and a black square represents a waste cell.  Now she is wondering how to determine the crop plants in some certain cells.

In the first line there are four positive integers n, m, k, t (1 ≤ n ≤ 4·104, 1 ≤ m ≤ 4·104, 1 ≤ k ≤ 103, 1 ≤ t ≤ 103), each of which represents the height of the field, the width of the field, the number of waste cells and the number of queries that ask the kind of crop plants in a certain cell. Following each k lines contains two integers a, b (1 ≤ a ≤ n, 1 ≤ b ≤ m), which denotes a cell (a, b) is waste. It is guaranteed that the same cell will not appear twice in this section. Following each t lines contains two integers i, j (1 ≤ i ≤ n, 1 ≤ j ≤ m), which is a query that asks you the kind of crop plants of a cell (i, j).

For each query, if the cell is waste, print Waste. Otherwise, print the name of crop plants in the cell: either Carrots or Kiwis or Grapes.

NoteThe sample corresponds to the figure in the statement.

Waste
Grapes
Carrots
Kiwis
Carrots
Carrots


Do you remember a kind cartoon "Beauty and the Beast"? No, no, there was no firing from machine guns or radiation mutants time-travels!There was a beauty named Belle. Once she had violated the Beast's order and visited the West Wing. After that she was banished from the castle... Everybody was upset. The beautiful Belle was upset, so was the Beast, so was Lumiere the candlestick. But the worst thing was that Cogsworth was upset. Cogsworth is not a human, but is the mantel clock, which was often used as an alarm clock.Due to Cogsworth's frustration all the inhabitants of the castle were in trouble: now they could not determine when it was time to drink morning tea, and when it was time for an evening stroll. Fortunately, deep in the basement are lying digital clock showing the time in the format HH:MM. Now the residents of the castle face a difficult task. They should turn Cogsworth's hour and minute mustache hands in such a way, that Cogsworth began to show the correct time. Moreover they need to find turn angles in degrees for each mustache hands. The initial time showed by Cogsworth is 12:00.You can only rotate the hands forward, that is, as is shown in the picture:   As since there are many ways too select such angles because of full rotations, choose the smallest angles in the right (non-negative) direction.Note that Cogsworth's hour and minute mustache hands move evenly and continuously. Hands are moving independently, so when turning one hand the other hand remains standing still.

The only line of input contains current time according to the digital clock, formatted as HH:MM (00 ≤ HH ≤ 23, 00 ≤ MM ≤ 59). The mantel clock initially shows 12:00. Pretests contain times of the beginning of some morning TV programs of the Channel One Russia.

Print two numbers x and y — the angles of turning the hour and minute hands, respectively (0 ≤ x, y < 360). The absolute or relative error in the answer should not exceed 10 - 9.

NoteA note to the second example: the hour hand will be positioned exactly in the middle, between 4 and 5.