pOH = -log~[OH^{-}]\\pOh=-log~(2^{-2}*10^{-3})\\pOH=-([-2]*log~2+[-3]*log~10)\\pOH=-([-2]*0,3010-3*1)\\pOH=-(-0,6020-3)\\pOH=-(-3,6020)\\pOH=3,6